Question

Сжимая пружину жёсткостью 40 Н/м, над ней совершили работу 2 Дж. Определите величину сжатия пружины.

Answer 1

Ответ:

32 см

Объяснение:

k=40 Н/м   A=2 Дж   x=?

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A=k*x²/2

x=√(2*A/k)=√(2*2/40)≈0.32 м

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Answer 2

Calculation of the Compression of a Spring

To determine the compression of a spring, we can use the formula for the potential energy stored in a spring:

Potential Energy (PE) = (1/2) * k * x^2

Where: - PE is the potential energy stored in the spring - k is the spring constant (stiffness) of the spring - x is the compression or extension of the spring

In this case, we are given the spring constant (k = 40 N/m) and the work done on the spring (W = 2 J). We can equate the work done to the potential energy stored in the spring:

W = PE

Substituting the formula for potential energy, we have:

2 J = (1/2) * 40 N/m * x^2

Simplifying the equation, we get:

x^2 = (2 J) / (20 N/m) = 0.1 m^2

Taking the square root of both sides, we find:

x = √(0.1) m ≈ 0.316 m

Therefore, the compression of the spring is approximately 0.316 meters.

Please note that the above calculation assumes that the spring obeys Hooke's Law and that the compression is within the elastic limit of the spring.