Question

Сила давления на поршень гидравдического пресса площадью 180см в квадрате ,равна 18 кН .Площадь меньшего поршня 4 см в квадрате.Какая сила приложена к меньшему поршню? 45б

Answer 1

Ответ:

400 Н

Объяснение:

Дано: S1=180 см²      F1=18000 H     S2=4 см²     F2=?

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p1=p2

F1/S1=F2/S2

F2=F1*S2/S1=18000*4/180=400 H

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Answer 2

Hydraulic Press Force Calculation

To calculate the force applied to the smaller piston, we can use the principle of Pascal's law, which states that the pressure applied to a fluid is transmitted undiminished throughout the fluid in all directions.

Given: - Area of the larger piston (A1) = 180 cm^2 - Force on the larger piston (F1) = 18 kN - Area of the smaller piston (A2) = 4 cm^2 - Force on the smaller piston (F2) = ?

We can use the formula: F1/A1 = F2/A2 to find the force on the smaller piston.

Calculation

Using the formula F1/A1 = F2/A2, we can solve for F2:

F2 = (F1 * A2) / A1

Substituting the given values: F2 = (18 kN * 4 cm^2) / 180 cm^2

Result

F2 = 0.4 kN

Therefore, the force applied to the smaller piston is 0.4 kN.

This calculation is based on the principles of Pascal's law and the given values for the areas and forces involved.

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