Question

Реши задачу Длина картины 47 см, а ширина на 21 см меньше. Найдите площадь и переметр картины. ​

Answer 1

Ответ:

1222см²

Пошаговое объяснение:

1). 47-21=26(см) ширина

2). (47+26)Х2=146(см) периметр

3) 47х26=1222(см2) площадь картины

Ответ 1222 см2 площадь

Answer 2

Problem Analysis

To find the area and perimeter of a rectangle, we need to know its length and width. In this case, we are given that the length of the painting is 47 cm, and the width is 21 cm less than the length.

Calculation

Let's calculate the width of the painting first. We know that the width is 21 cm less than the length, so we can subtract 21 from the length to find the width:

Width = Length - 21 cm = 47 cm - 21 cm = 26 cm

Now that we have the length and width, we can calculate the area and perimeter of the painting.

Area is calculated by multiplying the length and width of the rectangle:

Area = Length * Width = 47 cm * 26 cm = 1222 cm²

Perimeter is calculated by adding the lengths of all four sides of the rectangle:

Perimeter = 2 * (Length + Width) = 2 * (47 cm + 26 cm) = 2 * 73 cm = 146 cm

Answer

Therefore, the area of the painting is 1222 cm² and the perimeter is 146 cm.

I hope this helps! Let me know if you have any further questions.