Question

X² – 3x - 182)= 0;-​

Answer 1

Ответ:

6 и -3

Пошаговое объяснение:

x² – 3x - 18 =0

D = b²-4ac = -3² -4*(-18) = 9 + 72 = 81

корень 81 =9

x= -b +- 9

_____

2a

x1=(3+9)/2= 6

x2=(3-9)/2= -3

корни : 6 и -3

Answer 2

To solve the quadratic equation $x^2 - 3x - 182 = 0$, you can use the quadratic formula:

$x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$

In this equation, $a$ is the coefficient of $x^2$, $b$ is the coefficient of $x$, and $c$ is the constant term.

For your equation $x^2 - 3x - 182 = 0$, you have:

$a = 1$ $b = -3$ $c = -182$

Now, plug these values into the quadratic formula:

$x = \frac{-(-3) \pm \sqrt{(-3)^2 - 4(1)(-182)}}{2(1)}$

Simplify:

$x = \frac{3 \pm \sqrt{9 + 728}}{2}$ $x = \frac{3 \pm \sqrt{737}}{2}$

Now, you have two solutions for $x$:

1. $x = \frac{3 + \sqrt{737}}{2}$
2. $x = \frac{3 - \sqrt{737}}{2}$

These are the solutions to the quadratic equation $x^2 - 3x - 182 = 0$.