Question

3 sin(x+2 cos(x + 1) = 2​

Answer 1

Ответ:

2

Пошаговое объяснение:

x=3sin(x+2cos(x+1))

x=2

Answer 2

To solve the equation $3 \sin(x+2\cos(x+1)) = 2$, you can follow these steps:

1. Start by isolating the $\sin(x+2\cos(x+1))$ term on one side of the equation:

$3 \sin(x+2\cos(x+1)) = 2$

2. Divide both sides of the equation by 3 to isolate the sine function:

$\sin(x+2\cos(x+1)) = \frac{2}{3}$

3. Now, you want to find the inverse sine (also known as arcsin or sin^(-1)) of both sides to solve for $x$:

$x+2\cos(x+1) = \arcsin\left(\frac{2}{3}\right)$

4. To isolate $x$, you can subtract $2\cos(x+1)$ from both sides:

$x = \arcsin\left(\frac{2}{3}\right) - 2\cos(x+1)$

Now, this is the solution for $x$, but it's not in a closed-form analytical expression. To find a numerical approximation for $x$, you may need to use numerical methods or a calculator. The value of $\arcsin\left(\frac{2}{3}\right)$ can be calculated using a calculator, and you can then use iterative methods to approximate $x$ or use numerical software to find its value.