Question

1+2+...500=? Помогите ​

Answer 1

Ответ:

125 250

Пошаговое объяснение:

Это арифметическая прогрессия с разностью 1 и количеством членов n=500

S=(a₁+a₅₀₀)*500/2

Находим сумму: (1+500)*500:2=501*250=125 250

Answer 2

Sure, I can help you with that!

To find the sum of the numbers from 1 to 500, we can use the formula for the sum of an arithmetic series:

Sum = (n/2) * (first term + last term)

Where: n = number of terms first term = 1 last term = 500

So, in this case, n = 500 (there are 500 terms), the first term is 1, and the last term is 500.

Now, let's calculate the sum:

Sum = (500/2) * (1 + 500) Sum = 250 * 501 Sum = 125250

So, the sum of the numbers from 1 to 500 is 125250.