Question

Sin 63*cos27*+cos63*sin27*​

Answer 1

$\sin63^o\cos27^o+\cos63^o\sin27^o=\sin(63^o+27^o)=\sin90^o=1$

Answer 2

To simplify the expression sin(63)*cos(27) + cos(63)*sin(27), we can use the trigonometric identity:

sin(A + B) = sin(A)*cos(B) + cos(A)*sin(B)

Let's rewrite the expression using this identity:

sin(63)*cos(27) + cos(63)*sin(27) = sin(63 + 27)

Now we can calculate the sine of the sum of the angles:

sin(63 + 27) = sin(90) = 1

Therefore, the simplified expression is equal to 1.