Question

Log2(3x-6) =log2(2x-3) найти корни уравнений​

Answer 1

Ответ:

x=3

Пошаговое объяснение:

log2(3x-6) =log2(2x-3) , x є (2,+∞)

3x-6=2x-3

3x-2x=-3+6

x=3 , x є (2,+∞)

Answer 2

To solve the equation log2(3x - 6) = log2(2x - 3), we can use the property of logarithms that states if log(base a)(x) = log(base a)(y), then x = y.

In this case, we have log2(3x - 6) = log2(2x - 3), so we can set the expressions inside the logarithms equal to each other:

3x - 6 = 2x - 3

Now we can solve for x:

3x - 2x = -3 + 6

x = 3

Therefore, the equation log2(3x - 6) = log2(2x - 3) has a single root, x = 3.