Question

Оцените периметр и площадь прямоугольника со сторонами a см и b см где 6,2< a < 6,4; 13,3 < b 13,4. срочно​

Answer 1

Ответ:

39 < P < 39,6

82,46 < S < 85,76

Пошаговое объяснение:

1) Оценим периметр прямоугольника со сторонами a и b

P =2(a+b)

          6,2< a < 6,4

        13,3 < b < 13,4      

6,2+13,3 < a+b < 6,4+13,4

     19,5 < a+b < 19,8

2*19,5 < 2(a+b) < 2*19,8

    39 < 2(a+b) < 39,6

          39 < P < 39,6

1) Оценим площадь прямоугольника со сторонами a и b

S = ab

          6,2< a < 6,4

        13,3 < b < 13,4

6,2*13,3 < ab < 6,4*13,4

    82,46 < ab < 85,76

    82,46 < S < 85,76

Answer 2

Calculating the Perimeter and Area of a Rectangle

To calculate the perimeter and area of a rectangle with sides of length *a* cm and *b* cm, where 6.2 < *a* < 6.4 and 13.3 < *b* < 13.4, we can use the following formulas:

1. Perimeter (P) = 2(*a* + *b*) 2. Area (A) = *a* * *b*

Calculations

Given the range of values for *a* and *b*, we can calculate the perimeter and area as follows:

1. Perimeter (P) = 2(*a* + *b*) = 2(6.3 + 13.3) = 2(19.6) = 39.2 cm 2. Area (A) = *a* * *b* = 6.3 * 13.3 = 83.79 cm^2

So, the perimeter of the rectangle is 39.2 cm and the area is 83.79 cm^2.

These calculations are based on the given range of values for *a* and *b* and the formulas for perimeter and area of a rectangle.