Question

1. 0,6 a⁴b³*4a³b2. (-7x⁹y10)23)2a³(-5a⁴b⁵)²4)(3x²-2x)+(-x²-3x)​

Answer 1

Ответ:

Объяснение:

1) 0,6а⁴b³×4a³b=2,4a⁷b⁴

2) (–7x⁹y¹⁰)2= –14x⁹y¹⁰

Если в этом задании 2 за скобками обозначает вторую степень, то вычисление будет следующим:

2) (–7х⁹у¹⁰)²=49х¹¹у¹²

3) 2а³(–5а⁴b⁵)²=2a³×25a⁶b⁷=50a⁹b⁷

4) (3x²–2x)+(–x²–3x)=3x²–2x–x²–3x=2x²–5x

Answer 2

It looks like you've provided a mathematical expression that involves various terms and operations. Let's break down the expression and simplify it step by step:

1. 0.6a⁴b³ * 4a³b²: Multiply the coefficients (0.6 * 4 = 2.4) and add the exponents of the same variables (a⁴ * a³ = a⁷, b³ * b² = b⁵). Result: 2.4a⁷b⁵

2. (-7x⁹y¹⁰)²: Square both the coefficient and the variables' terms. Result: 49x¹⁸y²⁰

3. 2a³ * (-5a⁴b⁵)²: Multiply the coefficients (2 * (-5)² = 50) and add the exponents of the same variables (a³ * a⁸ = a¹¹, b⁵ * b¹⁰ = b¹⁵). Result: 50a¹¹b¹⁵

4. (3x² - 2x) + (-x² - 3x): Combine like terms by adding the coefficients of the same variables. Result: 3x² - 2x - x² - 3x = 2x² - 5x

Now, let's put all these simplified expressions together:

2.4a⁷b⁵ * 49x¹⁸y²⁰ * 50a¹¹b¹⁵ * (2x² - 5x)

Multiply the coefficients and variables' terms, and combine the polynomial terms:

2.4 * 49 * 50 * 2 = 117600 a⁷ * a¹¹ = a¹⁸ b⁵ * b¹⁵ = b²⁰ x¹⁸ * x² = x²⁰ y²⁰ remains the same -5x * 117600 = -588000x

The final expression is:

117600a¹⁸b²⁰x²⁰y²⁰ - 588000x