Question

Куб суммы (n+2m)^3помогитее♡

Answer 1

Куб суммы:
(a+b)³=a³+3a²b+3ab²+b³.
Следовательно:
(n+2m)³=n³+3n²·2m+3n·(2m)²+(2m)³=n³+6mn²+3n·4m²+8m³=n³+6mn²+12m²n+8m³.

Answer 2

Calculation of the Cube of the Sum (n + 2m)^3

To calculate the cube of the sum (n + 2m)^3, we can use the formula for expanding a binomial raised to a power. In this case, the binomial is (n + 2m) and the power is 3.

The formula for expanding a binomial raised to the power of 3 is:

[(a + b)^3 = a^3 + 3a^2b + 3ab^2 + b^3]

In our case, the binomial is (n + 2m), so we can substitute a = n and b = 2m into the formula.

Expanding (n + 2m)^3 using the formula, we get:

[(n + 2m)^3 = n^3 + 3n^2(2m) + 3n(2m)^2 + (2m)^3]

Simplifying further, we have:

[(n + 2m)^3 = n^3 + 6n^2m + 12nm^2 + 8m^3]

Therefore, the cube of the sum (n + 2m)^3 is equal to [n^3 + 6n^2m + 12nm^2 + 8m^3].

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