Question

Три бригады рабочих изготовили за смену 100 деталей. Вторая бригада изготовила на 5 деталей больше, чем первая бригада, и на 15 деталей больше,чем третья. Сколько деталей изготовила каждая бригада?

Answer 1

Пусть вторая бригада х деталей, первая х-5, третья х-15
х+х-5+х-15=100
3х-20=100
3х=100+20
3х=120
х=40 вторая бр.
40-5=35 первая бр
40-15=25 третья бр

Answer 2

Problem Analysis

We are given that three brigades of workers produced a total of 100 parts in one shift. The second brigade produced 5 more parts than the first brigade, and 15 more parts than the third brigade. We need to determine how many parts each brigade produced.

Solution

Let's assume that the first brigade produced x parts.

According to the given information, the second brigade produced 5 more parts than the first brigade, so the second brigade produced (x + 5) parts.

Similarly, the third brigade produced 15 fewer parts than the second brigade, so the third brigade produced (x + 5 - 15) = (x - 10) parts.

The total number of parts produced by all three brigades is 100, so we can write the equation:

x + (x + 5) + (x - 10) = 100

Simplifying the equation:

3x - 5 = 100

Adding 5 to both sides:

3x = 105

Dividing both sides by 3:

x = 35

Therefore, the first brigade produced 35 parts, the second brigade produced (35 + 5) = 40 parts, and the third brigade produced (35 - 10) = 25 parts.

Answer

The first brigade produced 35 parts, the second brigade produced 40 parts, and the third brigade produced 25 parts.