Question

Помогите пожалуйста!)на случайным образом выбранное поле шахматной доски 8✖8 поставили короля. Найдите вероятность что король оказался в угловой клетке.за ранее спасибо!

Answer 1

Всего клеток 64. А угловых клеток - 4. Значит вероятность, что король попадет именно туда равна

 

$P=\frac{4}{64}$

 

$P=\frac{1}{16}$

 

Answer 2

Probability of the King being in a Corner Square on a Randomly Selected Chessboard

To find the probability that a randomly placed king on an 8x8 chessboard ends up in a corner square, we need to determine the total number of possible positions for the king and the number of corner squares.

# Total Number of Possible Positions for the King

On an 8x8 chessboard, there are a total of 64 squares. Since the king can be placed on any of these squares, the total number of possible positions for the king is 64.

# Number of Corner Squares

A chessboard has four corner squares: a1, a8, h1, and h8. These are the squares where the rows and columns intersect at the edges of the board. Therefore, the number of corner squares is 4.

# Calculating the Probability

To calculate the probability, we divide the number of favorable outcomes (king in a corner square) by the total number of possible outcomes (total number of positions for the king).

The probability of the king being in a corner square is given by:

Probability = Number of corner squares / Total number of positions for the king

Substituting the values, we get:

Probability = 4 / 64 = 1 / 16

Therefore, the probability that a randomly placed king on an 8x8 chessboard ends up in a corner square is 1/16.

Please note that the above calculation assumes a random placement of the king on the chessboard and does not take into account any specific rules or constraints of the game.