Question

Розв'яжіть задачу, склавши рівняння. В одному ящику було 200 кг апельсинів, а в другому-120 кг. З першого ящика брали щоденно по 30 кг, а з другого по 25 кг. Через скільки днів у першому ящику залишиться в 4 рази більше апельсинів, ніж у другому?

Answer 1

В одном ящике было 200 кг апельсинов, а во втором-120 кг. С первого ящика брали ежедневно по 30 кг, а с другой по 25 кг. Через сколько дней в первом ящике останется в 4 раза больше апельсинов, чем во втором?
дни-x
(200-30x):4=120-25x/1
(200-30x)*1=(120-25x)*4
200-30x=480-100x
-30x+100x=480-200
70x=280:70
x=4

Answer 2

Task Solution: Solving the Equation

To solve this problem, we can use the following steps:

1. Calculate the number of days it takes for the first crate to have four times as many oranges left as the second crate. 2. Set up an equation to represent the situation and solve for the number of days.

Let's proceed with the solution.

Step 1: Calculate the Number of Days

The number of oranges in the first crate after x days can be represented by the equation: 200 - 30x. The number of oranges in the second crate after x days can be represented by the equation: 120 - 25x.

We want to find the value of x when the number of oranges in the first crate is four times the number of oranges in the second crate: 200 - 30x = 4 * (120 - 25x)

Step 2: Solve for x

Let's solve the equation to find the value of x.

200 - 30x = 480 - 100x Combine like terms: 100x - 30x = 480 - 200 70x = 280 x = 280 / 70 x = 4

Answer:

It will take 4 days for the first crate to have four times as many oranges left as the second crate.