Question

1/1+cos a+1/1-cos a= p.s как вообще представить единицу?

Answer 1

$\frac{1}{1+cosa}+ \frac{1}{1-cosa}= \frac{1-cosa+1+cosa}{(1-cosa)(1+cosa)}= \frac{2}{1-cos^2a}= \frac{2}{sin^2a+cos^2a-cos^2a} = \frac{2}{sin^2a}$

Answer 2

Solving the Equation 1/1 cos a + 1/1-cos a = p

To solve the equation 1/1 cos a + 1/1-cos a = p, we can start by simplifying the equation and then solving for the variable "a."

First, let's simplify the equation: 1/1 cos a + 1/1-cos a = p

We can rewrite the equation as: 1/cos a + 1/(1-cos a) = p

Now, to solve for "a," we can use algebraic manipulation to isolate "a" on one side of the equation.

Let's proceed with the solution.

Solution

To solve for "a," we can start by multiplying both sides of the equation by cos a * (1-cos a) to clear the denominators:

cos a * (1-cos a) * (1/cos a) + cos a * (1-cos a) * (1/(1-cos a)) = p * cos a * (1-cos a)

Simplifying the equation further: 1 - cos a + cos a = p * cos a * (1-cos a)

The terms "cos a" and "-cos a" cancel each other out: 1 = p * cos a * (1-cos a)

Now, we can rearrange the equation to solve for "a": 1/p = cos a * (1-cos a)

At this point, we can use trigonometric identities to further simplify the equation and solve for "a."

Trigonometric Identities

Using the trigonometric identity sin^2(a) + cos^2(a) = 1, we can express 1 - cos^2(a) as sin^2(a).

Substituting this into the equation: 1/p = cos a * sin^2(a)

Now, we can solve for "a" using the given equation.

Conclusion

The equation 1/1 cos a + 1/1-cos a = p can be simplified and solved for "a" using trigonometric identities and algebraic manipulation. The final solution for "a" will be in terms of the variable "p."