Question

Разложите на множители 1) a^2-ab-3b+3a 2 )ax -at +cy-cx-x+y заранее спасибо

Answer 1

$1)a^2-ab-3b+3a=a(a-b)+3(a-b)=(a-b)(a+3) \\ \\ 2)ax-ay+cy-cx-x+y=a(x-y)+c(y-x)-x+y=a(x-y) \\ -(x-y)(c+1)=(x-y)(a-(c+1))=(x-y)(a-c-1)$

Answer 2

1)=a(a+3)-b(a+3)=(a+3)(a-b)
Bo 2 точно есть буква t?

Answer 3

Factoring Expressions

To factor the given expressions, let's start with the following:

1) a^2 - ab - 3b + 3a

We can factor this expression by grouping: ``` a^2 - ab - 3b + 3a = a(a - b) - 3(b - a) = a(a - b) - 3(-(a - b)) = a(a - b) + 3(a - b) = (a + 3)(a - b) ```

Therefore, the factored form of the expression is (a + 3)(a - b).

2) ax - at + cy - cx - x + y

We can factor this expression by grouping as well: ``` ax - at + cy - cx - x + y = a(x - t) - c(x - y) - (x - y) = a(x - t) - c(x - y) - 1(x - y) = (a - c - 1)(x - y) ```

Therefore, the factored form of the expression is (a - c - 1)(x - y).

I hope this helps! If you have any more questions or need further assistance, feel free to ask.