Question

4с(с-2)-(с-4) ( С-4) в квадрате3(y-1)+6y (y-1) в квадрате

Answer 1

1) 4c^2-8c-c+4=4c^2-9c+4

2)(c-4)^2=c^2-8c+16

3)3(y-1)+6y=3y-3+6y=9y-3

4)(y-1)^2=y^2-2y+1

 

 

 

 

 

 

Answer 2

4с(с-2)-(с-4)^2=4c^2-8c-(c^2-8c+16)=4c^2-8c-c^2+8c-16=3c^2-16   (^2-в квадрате)

3(y-1)^2+6y =3(y^2-2y+1)+6y=3y^2-6y+3+6y=3y^2+3=3(y^2+1) 

Answer 3

I can help you with your math problem. Here is the detailed solution:

First, let's simplify the expression by expanding the brackets and combining like terms. We get:

$$4c(c-2)-(c-4)(c-4)+3(y-1)+6y+(y-1)(y-1)$$ $$=4c^2-8c-c^2+8c-16+3y-3+6y+y^2-2y+1$$ $$=3c^2+7y+y^2-18$$

Next, let's factorize the expression by grouping the terms. We get:

$$=3c^2+7y+y^2-18$$ $$=(3c^2+y^2)+(7y-18)$$ $$=c^2(3+y)+(7y-18)$$

Finally, let's factorize the expression further by finding the common factors. We get:

$$=c^2(3+y)+(7y-18)$$ $$=c^2(3+y)+7(y-18/7)$$ $$=(c^2+7)(3+y-18/7)$$

Therefore, the final answer is:

$$4c(c-2)-(c-4)(c-4)+3(y-1)+6y+(y-1)(y-1)$$ $$=(c^2+7)(3+y-18/7)$$

I hope this helps. Have a nice day!Ответь+подробно.+4с(с-2)-(с-4)+(+С-4)+в+квадрате3(y-1)+6y+(y-1)+в+квадрате