Question

Сократите дробь:

Answer 1

$\frac{(1-3a)^{2}}{3a^{2}+5a-2}$

 

$D=25+4*3*2=49$

 

$a_{1}=\frac{-5+7}{6}=\frac{2}{6}=\frac{1}{3}, a_{2}=\frac{-5-7}{6}=-2$

 

$\frac{(1-3a)^{2}}{3a^{2}+5a-2}=\frac{(1-3a)^2}{3(a-\frac{1}{3})(a+2)}=\frac{(1-3a)^{2}}{(3a-1)(a+2)}=\frac{(3a-1)^{2}}{(3a-1)(a+2)}=\frac{3a-1}{a+2}$