Question

Pleas, Help me! -> 22/х-3=3/х-22

Answer 1

$\frac{22}{x-3} = \frac{3}{x-22} \\ x \neq 3 \\ x \neq 22 \\ 22*(x-22)=3(x-3) \\ 22x-484=3x-9 \\ 19x=475 \\ x=25$

Answer 2

I can help you with your math problem.

The problem you have is: $$\frac{22}{x-3}=\frac{3}{x-22}$$

To solve this, you need to find the value of x that makes the equation true. One way to do this is to cross-multiply, which means multiplying both sides of the equation by the denominators of the fractions. This will give you:

$$(x-3)(x-22)=22 \times 3$$

Then, you need to expand the brackets and simplify the equation. This will give you:

$$x^2-25x+66=66$$

Subtracting 66 from both sides, you get:

$$x^2-25x=0$$

To solve this quadratic equation, you can either factorize it or use the quadratic formula. In this case, factorizing is easier. You need to find two numbers that multiply to 0 and add to -25. These numbers are -5 and -20. So, you can write the equation as:

$$(x-5)(x-20)=0$$

Then, you can use the zero product property, which says that if the product of two factors is zero, then one of the factors must be zero. This means that either x-5=0 or x-20=0. Solving for x, you get:

$$x=5 \text{ or } x=20$$

These are the two possible solutions for x. You can check them by plugging them back into the original equation and see if they make it true.

I hope this helps you understand how to solve this problem. If you need more help, you can use this [online calculator] to check your answers and see the steps. Have a nice day!Ответь подробно. Pleas, Help me! -> 22/х-3=3/х-22