Question

Карлсон пролетел по ветру 3ч и 2ч против ветра.Определите скорость Карлсона в безветренную погоду,если скорость ветра равна 5км/ч,а всего он пролетел 55км.

Answer 1

Х - скорость без ветра
х+5 по ветру
х-5 против ветра
(х+5)*3+(х-5)*2=55
3х+15+2х-10=55
5х+5=55
5х=50
х=10 - скорость без ветра
проверка
15 по ветру
5 против ветра
15*3+5*2=45+10=55

Answer 2

Calculation of Karlsson's Speed in Still Weather

To determine Karlsson's speed in still weather, we need to consider the information provided:

- Karlsson flew for 3 hours with the wind. - Karlsson flew for 2 hours against the wind. - The wind speed is 5 km/h. - Karlsson flew a total distance of 55 km.

Let's break down the problem step by step:

1. Calculate the distance Karlsson flew with the wind: - Karlsson's speed with the wind can be represented as: (Karlsson's speed in still weather) + (wind speed) - Karlsson flew for 3 hours with the wind, so the distance covered is: 3 * (Karlsson's speed in still weather + 5).

2. Calculate the distance Karlsson flew against the wind: - Karlsson's speed against the wind can be represented as: (Karlsson's speed in still weather) - (wind speed) - Karlsson flew for 2 hours against the wind, so the distance covered is: 2 * (Karlsson's speed in still weather - 5).

3. Set up an equation using the total distance covered: - The total distance Karlsson flew is 55 km, so we can set up the equation: 3 * (Karlsson's speed in still weather + 5) + 2 * (Karlsson's speed in still weather - 5) = 55.

Now, let's solve the equation to find Karlsson's speed in still weather.

Solving the Equation

Expanding the equation, we get:

3 * Karlsson's speed in still weather + 15 + 2 * Karlsson's speed in still weather - 10 = 55

Combining like terms:

5 * Karlsson's speed in still weather + 5 = 55

Subtracting 5 from both sides:

5 * Karlsson's speed in still weather = 50

Dividing both sides by 5:

Karlsson's speed in still weather = 10 km/h

Therefore, Karlsson's speed in still weather is 10 km/h.

Please note that the provided search snippet does not directly answer the question. However, the calculation provided above is based on the given information and does not require additional sources.