Question

*Представить в виде многочлена* 1.1 ) (3в- 2с)2= 1.2 ) (х+2у)2= 1.3 ) 25а2-16в2= 1.4 ) (2а+3в)(2а-3в)= *Срочно помощь нужна*

Answer 1

Объяснение:

надеюсь помог........

Answer 2

1.1) (1.1) + (3v - 2c)^2 = 1.2 + (x + 2y)^2 = 1.3 + 25a^2 - 16b^2 = 1.4 + (2a + 3b)(2a - 3b)

To represent these expressions as polynomials, we need to expand and simplify each expression.

Let's go through each expression one by one:

1.1) (1.1) + (3v - 2c)^2:

To expand the square of a binomial, we use the formula: (a + b)^2 = a^2 + 2ab + b^2.

In this case, we have (3v - 2c)^2. Using the formula, we get:

(3v - 2c)^2 = (3v)^2 + 2(3v)(-2c) + (-2c)^2 = 9v^2 - 12vc + 4c^2

So, the expression (1.1) + (3v - 2c)^2 can be represented as the polynomial: 1.1 + 9v^2 - 12vc + 4c^2.

1.2) 1.2 + (x + 2y)^2:

Using the same formula as above, we can expand (x + 2y)^2:

(x + 2y)^2 = x^2 + 2(x)(2y) + (2y)^2 = x^2 + 4xy + 4y^2

So, the expression 1.2 + (x + 2y)^2 can be represented as the polynomial: 1.2 + x^2 + 4xy + 4y^2.

1.3) 25a^2 - 16b^2:

This expression is already in the form of a polynomial. It represents the difference of two squares, which can be factored as (a + b)(a - b). In this case, we have:

25a^2 - 16b^2 = (5a)^2 - (4b)^2 = (5a + 4b)(5a - 4b)

So, the expression 25a^2 - 16b^2 can be represented as the polynomial: (5a + 4b)(5a - 4b).

1.4) (2a + 3b)(2a - 3b):

This expression is also in the form of a polynomial. It represents the difference of two squares, which can be factored as (a + b)(a - b). In this case, we have:

(2a + 3b)(2a - 3b) = (2a)^2 - (3b)^2 = 4a^2 - 9b^2

So, the expression (2a + 3b)(2a - 3b) can be represented as the polynomial: 4a^2 - 9b^2.

I hope this helps! Let me know if you have any further questions.