Question

Обчислить √32•√2-√48-√3​

Answer 1

$\displaystyle\bf\\\sqrt{32} \cdot\sqrt{2} -\sqrt{48} \cdot\sqrt{3} =\sqrt{32\cdot 2} -\sqrt{48\cdot 3} =\sqrt{16\cdot 4} -\sqrt{16\cdot 9}=\\\\=4\cdot 2-4\cdot 3=8-12=-4$

Answer 2

Ответ:

Объяснение:

√32•√2-√48-√3​=√32•2-√16•3 -√3=√64 - 4√3 - √3= 8 - 5√3

Answer 3

√32•√2-√48-√3

First, let's simplify the square roots: √32 = √(16*2) = 4√2 √48 = √(16*3) = 4√3 √3 = √3

Now we can substitute these simplified square roots back into the original expression: 4√2 * √2 - 4√3 - √3

Now, we can simplify further: 4√2 * √2 = 4*2 = 8 8 - 4√3 - √3

Combining like terms: 8 - 5√3

So, the final simplified expression is: 8 - 5√3