Question

Реши систему уравнений способом алгебраического сложения. {2a+5y=6 {3a+7y=10 Ответ: a= y= Смотреть ответ kristinabezmelnicina kristinabezmelnicina Ответ: { 2a + 5y  = 6            |* 3 { 3a  + 7y  = 10         | *(-2) { 6a  + 15y  = 18 { -6a - 14y  =  - 20 (6a + 15y)  + ( - 6a - 14y) = 18 + (-20) (6a - 6a)  + (15y  - 14y) =  - 2 y  = - 2 2a  + 5*(-2) =  6 2a  - 10  = 6 2a  = 6 + 10 2a = 16 a = 16 : 2 а = 8. Объяснение: та незашто, всегда рада помочь Спасибо большое

Answer 1

Solving the System of Equations using Algebraic Addition

To solve the system of equations using algebraic addition, we will follow these steps:

1. Write down the given equations: - Equation 1: 2a + 5y = 6 - Equation 2: 3a + 7y = 10

2. Multiply both sides of Equation 1 by 3 and Equation 2 by 2 to make the coefficients of 'a' equal: - Equation 1 (after multiplication): 6a + 15y = 18 - Equation 2 (after multiplication): 6a + 14y = 20

3. Subtract Equation 2 from Equation 1 to eliminate 'a': - (6a + 15y) - (6a + 14y) = 18 - 20 - Simplifying, we get: y = -2

4. Substitute the value of 'y' (-2) into either Equation 1 or Equation 2 to solve for 'a'. Let's use Equation 1: - 2a + 5(-2) = 6 - Simplifying, we get: 2a - 10 = 6 - Adding 10 to both sides, we get: 2a = 16 - Dividing both sides by 2, we get: a = 8

5. Therefore, the solution to the system of equations is: - a = 8 - y = -2

So, the values of 'a' and 'y' that satisfy both equations are 'a = 8' and 'y = -2'.

I hope this explanation helps! Let me know if you have any further questions.