Question

1) 23-√23 ______ √23 2) Х-9 ______ √Х-3

Answer 1

Ответ:

(23-√23)/√23=(23*√23-23)/23=√23-1

Объяснение:

Answer 2

Сокращаем первую скобку и нижнее значения, получается корень с икса плюс 3

Answer 3

1. To simplify the expression 23 - √23 over √23, you can first factor out √23 from the numerator:

(23 - √23) / √23

Now, to rationalize the denominator, multiply both the numerator and denominator by √23:

[(23 - √23) / √23] * [√23 / √23]

This simplifies to:

(23√23 - 23) / 23

2. To simplify the expression Х - 9 over √Х - 3, you can first factor out the common factor of 3 from the denominator:

(X - 9) / (√X - 3)

Now, to rationalize the denominator, multiply both the numerator and denominator by the conjugate of the denominator, which is (√X + 3):

[(X - 9) / (√X - 3)] * [(√X + 3) / (√X + 3)]

This simplifies to:

(X - 9)(√X + 3) / (X - 9)

Now, you can cancel out the common factor of (X - 9) from the numerator and denominator:

√X + 3

So, the simplified expression is √X + 3.