Question

X2+6x-12=0. help ĥhhhhhhhhhh​

Answer 1

Ответ:

Объяснение: найдем D=b^2-4ac=6^2-4*1*(-12)=84

тогда х1=(-b+√D)/2a=-6+√84/2*1=-3+√21

x2=-3-√21

Answer 2

To solve the quadratic equation x^2 + 6x - 12 = 0, you can use the quadratic formula:

x = (-b ± √(b² - 4ac)) / (2a)

In this equation, a = 1, b = 6, and c = -12. Plug these values into the formula:

x = (-6 ± √(6² - 4 * 1 * (-12))) / (2 * 1)

x = (-6 ± √(36 + 48)) / 2

x = (-6 ± √(84)) / 2

Now, simplify the square root:

x = (-6 ± √(4 * 21)) / 2

x = (-6 ± 2√21) / 2

Now, you can simplify further by dividing both the numerator and the denominator by 2:

x = -3 ± √21

So, the solutions to the equation x^2 + 6x - 12 = 0 are:

x = -3 + √21 x = -3 - √21

These are the two values of x that satisfy the equation.