Question

(a - х степенi 0,5) (a + х степенi 0,5)

Answer 1

$(a-x^{0.5})(a+x^{0.5})=a^2-(x^{0.5})^2=a^2-x$

Answer 2

It looks like you want to multiply the expressions (a - x^0.5) and (a + x^0.5). You can do this using the distributive property or the difference of squares formula.

Using the distributive property: (a - x^0.5)(a + x^0.5) = a * a + a * x^0.5 - x^0.5 * a - x^0.5 * x^0.5 = a^2 + a * x^0.5 - a * x^0.5 - x

The middle terms (a * x^0.5 and -a * x^0.5) cancel out, leaving you with: a^2 - x

So, the product of (a - x^0.5) and (a + x^0.5) is equal to a^2 - x.