Question

X^2-2x-y^2-2y пожалуйста помогите

Answer 1

X²- 2x-y²-2y=(x²-y²)-(2x+2y)=(x+y)(x-y)-2(x+y)=(x+y)(x-y-2).

Answer 2

Solving the Equation x^2 - 2x - y^2 - 2y

To solve the equation x^2 - 2x - y^2 - 2y, we can use the given equation to find the values of x and y that satisfy it.

The given equation is: x^2 - 2x - y^2 - 2y

To solve for x and y, we can use the following steps:

1. Complete the square for x. 2. Complete the square for y. 3. Solve for x and y.

Let's proceed with these steps.

Completing the Square for x

To complete the square for x, we can use the formula: x^2 - 2x + ( -2 / 2)^2 = (x - 1)^2 - 1

Completing the Square for y

To complete the square for y, we can use the formula: -y^2 - 2y + ( -2 / 2)^2 = -(y + 1)^2 + 1

Solving for x and y

Now, we can set the equation equal to zero and solve for x and y:

x^2 - 2x - y^2 - 2y = 0

=> (x - 1)^2 - 1 - (y + 1)^2 + 1 = 0

=> (x - 1)^2 - (y + 1)^2 = 0

This equation represents a pair of intersecting lines, and the solutions for x and y will be the points of intersection.

By solving the above equation, we can find the values of x and y that satisfy the given equation.

The solutions for x and y are: - (x, y) = (1, 2) - (x, y) = (2, 1)

These are the points that satisfy the given equation x^2 - 2x - y^2 - 2y.

I hope this helps! If you have any further questions, feel free to ask.