Question

2^(x-1)*5^(x-1)=10^(2x+5)

Answer 1

Iyi dersler ^-^/////////

Answer 2

To solve the equation $2^{x-1} \cdot 5^{x-1} = 10^{2x+5}$, we can use the fact that $10 = 2 \cdot 5$.

Let's rewrite $10^{2x+5}$ as $(2 \cdot 5)^{2x+5}$:

$2^{x-1} \cdot 5^{x-1} = (2 \cdot 5)^{2x+5}$

Now we can simplify the right-hand side:

$2^{x-1} \cdot 5^{x-1} = 2^{2x+5} \cdot 5^{2x+5}$

Since the bases are the same, we can equate the exponents:

$x - 1 = 2x + 5$

Now, solve for $x$:

$x - 2x = 5 + 1$

$-x = 6$

$x = -6$

So, the solution to the equation is $x = -6$.