Question

7sin8a/5cos4a Sin4a=0,35

Answer 1

=550син кун кин6786689

Answer 2

It seems like you have an equation involving trigonometric functions that you'd like to solve for the variable "a." The equation you've provided is:

(7sin(8a))/(5cos(4a)) * sin(4a) = 0.35

To solve for "a," you can start by simplifying the equation. First, notice that sin(4a) appears in both the numerator and denominator, so you can cancel it out:

(7sin(8a))/(5cos(4a)) * sin(4a) = 0.35

(7sin(8a))/(5cos(4a)) = 0.35

Now, you can multiply both sides of the equation by 5cos(4a) to isolate the sin(8a) term:

7sin(8a) = 0.35 * 5cos(4a)

7sin(8a) = 1.75cos(4a)

Now, divide both sides of the equation by 7 to solve for sin(8a):

sin(8a) = 1.75cos(4a)/7

Next, you can use the identity sin^2(x) + cos^2(x) = 1 to express cos(4a) in terms of sin(4a):

sin(8a) = 1.75 * (1 - sin^2(4a))/7

Now, you have an equation involving sin(4a) and sin(8a). You can try to simplify it further, but it's a bit complex. You might consider numerical methods or a calculator to approximate the solution for "a" unless you have specific values for sin(8a) and sin(4a) provided in the problem.