Question

1. 6^(-4):6^(-5)= x^(-2)*x^(-3)=

Answer 1

Ответ:

Объяснение:

по свойствам степени:

1) (6⁻⁴) : (6⁻⁵) = 6 ⁻⁴ ⁺⁵ = 6 ¹ = 6

2) х⁻² · х⁻³ = х ⁻² ⁺ ⁽⁻³⁾ = х ⁻² ⁻³ =х ⁻⁵

Answer 2

To simplify the expression $6^{-4}:6^{-5}$, you can use the rule that when you divide two numbers with the same base and different exponents, you subtract the exponents:

$6^{-4}:6^{-5} = 6^{-4 - (-5)} = 6^{1} = 6$

Now, for the expression $x^{-2} \cdot x^{-3}$, you can use the rule that when you multiply two numbers with the same base and different exponents, you add the exponents:

$x^{-2} \cdot x^{-3} = x^{(-2) + (-3)} = x^{-5}$

So, the value of $x^{-2} \cdot x^{-3}$ is $x^{-5}$.

Now, if you want to express your final answer in a single expression, you can combine the results:

$\frac{6^{-4}}{6^{-5}} \cdot x^{-2} \cdot x^{-3} = 6 \cdot x^{-5}$

So, $x^{-2} \cdot x^{-3} = 6 \cdot x^{-5}$.