Question

(2x+1)(x-4) = (x-2)(x+2)

Answer 1

Ответ:

корни уравнения 7 и 0

Объяснение:

Слева и справа раскроем скобки

2x²-8x+x-4=x²-4

x²-7x=0

x(x-7)=0

x=0 ; x=7

Answer 2

To solve the equation (2x+1)(x-4) = (x-2)(x+2), you can follow these steps:

1. Expand both sides of the equation:

On the left side: (2x+1)(x-4) = 2x(x) + 2x(-4) + 1(x) + 1(-4) = 2x^2 - 8x + x - 4 = 2x^2 - 7x - 4

On the right side: (x-2)(x+2) = x(x) + x(2) - 2(x) - 2(2) = x^2 + 2x - 2x - 4 = x^2 - 4

So, the equation becomes: 2x^2 - 7x - 4 = x^2 - 4

2. Now, you can simplify the equation by subtracting x^2 and 4 from both sides:

2x^2 - x^2 - 7x - 4 + 4 = 0

x^2 - 7x = 0

3. Factor out the common term "x" from both terms on the left side:

x(x - 7) = 0

4. Set each factor equal to zero:

x = 0 x - 7 = 0

5. Solve for "x" in each equation:

For x = 0: x = 0

For x - 7 = 0: x = 7

So, the solutions to the equation (2x+1)(x-4) = (x-2)(x+2) are x = 0 and x = 7.