Question

(9с² + d²) (3с-d)( 3с + d)​

Answer 1

Ответ:

Объяснение:

(9с² + d²) (3с-d)( 3с + d)​= (9c²+d²)(9c²-d²)= 81c⁴-d⁴

Answer 2

Объяснение:

$(3c - d)(3c + d) = 9c {}^{2} - d {}^{2}$

$(9c {}^{2} + d {}^{2} )(9c { }^{2} - d {}^{2}) = 81c {}^{4} - d {}^{4}$

Answer 3

To expand the expression (9c² + d²)(3c - d)(3c + d), you can use the distributive property, also known as the FOIL method (First, Outer, Inner, Last). Here's how you can expand it step by step:

First, let's multiply the first two terms (9c² + d²) and (3c - d):

(9c² + d²)(3c - d) = 9c² * 3c + 9c² * (-d) + d² * 3c + d² * (-d)

Now, perform the multiplications:

27c³ - 9cd + 3cd² - d³

Next, let's multiply the result by (3c + d):

(27c³ - 9cd + 3cd² - d³)(3c + d)

Using the distributive property again, multiply each term in the first expression by each term in the second expression:

27c³ * 3c + 27c³ * d - 9cd * 3c - 9cd * d + 3cd² * 3c + 3cd² * d - d³ * 3c - d³ * d

Now, perform the multiplications:

81c⁴ + 81c³d - 27c²d - 9cd² + 9c²d² + 3cd³ - 3c⁴ - d⁴

Now, you can simplify the expression by combining like terms:

81c⁴ - 3c⁴ + 81c³d - 27c²d + 9c²d² - 9cd² + 3cd³ - d⁴

Finally, simplify further:

78c⁴ + 81c³d - 27c²d + 9c²d² - 9cd² + 3cd³ - d⁴

So, the expanded form of (9c² + d²)(3c - d)(3c + d) is 78c⁴ + 81c³d - 27c²d + 9c²d² - 9cd² + 3cd³ - d⁴.