Question

(2x+3)-4(x+1)(x-1)=49

Answer 1

Ответ:

2x+3-(x^2-1)=49

2x+3-4x^2 +4=49

2x+7-4x^2=49

2x+7-4x^2-49=0

2x-42-4x^2=0

-4x^2+2x-42=0

2x^2-x+21=0

D=(-1)^2-4×2×21=1-168=-167<0

Объяснение:

Ответ

Answer 2

To solve the equation (2x+3)-4(x+1)(x-1)=49, you can follow these steps:

1. Expand the expressions: 2x + 3 - 4(x+1)(x-1) = 49

2. Expand the quadratic term in the middle: 2x + 3 - [4(x^2 - 1)] = 49

3. Distribute the -4 inside the brackets: 2x + 3 - 4x^2 + 4 = 49

4. Combine like terms on the left side of the equation: 2x - 4x^2 + 7 = 49

5. Move 49 to the left side by subtracting it from both sides of the equation: 2x - 4x^2 + 7 - 49 = 0

6. Combine like terms: -4x^2 + 2x - 42 = 0

7. To solve this quadratic equation, you can use the quadratic formula: x = (-b ± √(b² - 4ac)) / (2a)

   In this case, a = -4, b = 2, and c = -42. Plug these values into the formula:

   x = (-2 ± √(2² - 4(-4)(-42))) / (2*(-4))

8. Calculate the discriminant (the value inside the square root): Discriminant = 2² - 4*(-4)*(-42) = 4 - 672 = -668

Since the discriminant is negative, there are no real solutions to this quadratic equation. If you want to find complex solutions, you can proceed using the quadratic formula with the negative discriminant. The solutions will involve imaginary numbers.