Question

Sin^2*7п/12*cos^2*7п/12​

Answer 1

Объяснение:

$sin^2(\frac{7\pi }{12})*cos^2(\frac{7\pi }{12})=( sin(\frac{7\pi }{12})*cos(\frac{7\pi }{12}))^2= ( \frac{2*sin(\frac{7\pi }{12})*cos(\frac{7\pi }{12})}{2} )^2=\\=(\frac{sin(\frac{7\pi }{6}) }{2} )^2=(\frac{-\frac{1}{2} }{2} )^2=(-\frac{1}{4})^2=\frac{1}{16}.$

Answer 2

It appears that you want to calculate the value of the expression:

sin^2(7π/12) * cos^2(7π/12)

To calculate this, you can use trigonometric identities. First, note that:

sin^2(x) + cos^2(x) = 1

So, you can rewrite sin^2(7π/12) as 1 - cos^2(7π/12). Now, the expression becomes:

(1 - cos^2(7π/12)) * cos^2(7π/12)

Now, you can multiply the terms:

(1 - cos^2(7π/12)) * cos^2(7π/12) = cos^2(7π/12) - cos^4(7π/12)

You can further simplify this if you know the value of cos(7π/12). If you need a numerical approximation, you can calculate it using a calculator or a trigonometric table.