Question

1) 7x-xy-7+y 2)y^8+y^6-6y^2-6 3)12xy-3y+4x^2-x

Answer 1

Ответ:

$1) 7*(x-1)-y(x-1)=(x-1)(7-y)\\\\2) (y^8+y^6)*(-6y^2-6)=y^6(y^2+1)-6(y^2+1)=(y^2+1)(y^66)\\\\3) (12xy-4x^2)(3y-x)=4x(3y-x)(3y-x)=4x(3y-x)^2=4x(9y^2-6xy+x^2)=36xy^2-24x^2y+4x^3$

Объяснение:

Answer 2

It looks like you've provided three different algebraic expressions. It seems like you might want me to simplify these expressions or perform some operations on them. Let's go through each expression one by one:

1) $7x - xy - 7 + y$

To simplify this expression, you can factor out the common terms:

$7x - xy - 7 + y = x(7 - y) + (y - 7)$

So, the simplified form of the expression is $x(7 - y) + (y - 7)$.

2) $y^8 + y^6 - 6y^2 - 6$

There's no common factor in this expression, so it can't be simplified further.

3) $12xy - 3y + 4x^2 - x$

To simplify this expression, you can group the terms with $x$ and $y$:

$12xy - 3y + 4x^2 - x = x(12y - 1) + y(-3 + 0)$

So, the simplified form of the expression is $x(12y - 1)$.

If you need to perform any specific operations with these expressions or if you have any other questions, feel free to let me know!