Question

1) y = 2x², y = 0,5x®, yy = 2x2 + 1;2222​

Answer 1

Ответ:

Объяснение:сложно сказать

Answer 2

It seems like there might be a few typographical errors in your equations. Let's correct them and work with the equations as follows:

1. The first equation is y = 2x².
2. The second equation is y = 0.5x² (I assume you meant to write x² instead of x®).
3. The third equation is not clear. I'm assuming you meant y = 2x² + 1.

Now, let's solve these equations:

1. y = 2x²
2. y = 0.5x²
3. y = 2x² + 1

To find their solutions:

1. For the first equation, y = 2x², there is no explicit condition given, so it represents a parabola opening upward.

2. For the second equation, y = 0.5x², it is also a parabola but opens upward and is stretched compared to the first equation.

3. For the third equation, y = 2x² + 1, it represents a parabola that opens upward and is shifted upward by 1 unit compared to the first equation.

If you have specific questions or need to solve for particular values or intersections of these equations, please provide more information, and I'd be happy to assist further.