Question

(x²+x+1)2+3x(x²+x+1)-18x²​

Answer 1

Решение:

(x² + x + 1) · 2 + 3x · (x² + x + 1) - 18x²​ =

= 2x² + 2x + 2 + 3x³ + 3x² + 3x - 18x² =

= 3x³ - 13 x² + 5x + 2

Answer 2

To simplify the given expression $(x^2+x+1) \times 2 + 3x(x^2+x+1) - 18x^2$, first, expand the terms within the parentheses and then combine like terms.

1. Expand $(x^2+x+1) \times 2$: $2(x^2) + 2(x) + 2(1) = 2x^2 + 2x + 2$

2. Expand $3x(x^2+x+1)$: $3x(x^2) + 3x(x) + 3x(1) = 3x^3 + 3x^2 + 3x$

3. Now, the given expression becomes: $2x^2 + 2x + 2 + 3x^3 + 3x^2 + 3x - 18x^2$

4. Combine like terms: $2x^2 + 3x^2 - 18x^2 + 2x + 3x = -10x^2 + 5x$

So, the simplified form of the given expression is $-10x^2 + 5x$.