Question

B^3/63x^4•7x^4/b^12 Пжжжж

Answer 1

$\dfrac{b^{3} }{63x^{4} } \cdot\dfrac{7x^{4} }{b^{12} } =\dfrac{b^{3}\cdot 7 }{7\cdot 9\cdot b^{3} \cdot b^{9} } =\boxed{\dfrac{1}{9b^{9} } }$

Answer 2

It seems like you've provided an expression with variables and numbers. Let's break it down and simplify it step by step:

Expression: (B^3 / 63) * (x^4 * 7x^4) / B^12

Step 1: Simplify the numerator and denominator separately.

Numerator: (B^3 / 63) * (x^4 * 7x^4) = (B^3 / 63) * (7x^8)

Denominator: B^12

Step 2: Now, divide the numerator by the denominator.

(B^3 / 63) * (7x^8) / B^12

Step 3: To simplify further, subtract the exponents of 'B' in the numerator and denominator since they have the same base 'B'.

(B^(3 - 12) / 63) * (7x^8)

Step 4: Simplify the exponent of 'B'.

(B^(-9) / 63) * (7x^8)

Step 5: Multiply the constants in the numerator and denominator.

(7/63) * (B^(-9)) * (7x^8)

Step 6: Simplify the constants.

(1/9) * (B^(-9)) * (7x^8)

So, the simplified expression is:

(1/9) * (7x^8 / B^9)

You can further simplify this expression if needed, depending on your specific requirements.