Question

6²-(-1/12)⁰+(4)²:2=?​

Answer 1

Ответ:

43

Объяснение:

36-1+2^4:2=36-1+2^3=36-1+8=43

Answer 2

${6}^{2} - ( - \frac{1}{12} ) {}^{0} + {(4)}^{2} \div 2 = \\ 36 - 1 + 2 {}^{} {}^{4} \div 2 {}^{1} = \\ = 36 - 1 + 2 {}^{4 - 1} = 36 - 1 + 2 {}^{3} = 36 - 1 + 8 = 43$

Answer 3

To solve this expression, you should follow the order of operations (PEMDAS/BODMAS), which stands for Parentheses/Brackets, Exponents/Orders (i.e., powers and square roots, etc.), Multiplication and Division (left-to-right), and Addition and Subtraction (left-to-right). In this case, you don't have any parentheses or exponents, so you can perform the multiplication and division first, and then the addition and subtraction.

Here's how you should solve it step by step:

1. Calculate 6², which is 6 * 6 = 36.
2. Calculate (-1/12)⁰. Any nonzero number raised to the power of 0 is equal to 1, so (-1/12)⁰ = 1.
3. Calculate 4², which is 4 * 4 = 16.
4. Divide 16 by 2, which is 16 / 2 = 8.

Now, you have the expression as follows:

36 - 1 + 8

5. Subtract 1 from 36, which is 36 - 1 = 35.
6. Finally, add 8 to 35, which is 35 + 8 = 43.

So, the answer is 43.