Question

(x+3)(x-10)<(x-5)(x+2)​

Answer 1

Ответ:

Смотри решение на фото...

Answer 2

С ТЕБЯ 50 БАЛОВ

Ответ:

x>-5

Объяснение:

(х+3)(х-10) < (х-5)(х-2)

х²-10х+3х-30 < х²-2х-5х+10

х²-7х-30 < х²-7х+10

-30 < 10

-7x-30<-3x-10

-7x+3x<-10+30

-4x<20

x>-5

Answer 3

To solve the inequality $(x+3)(x-10) < (x-5)(x+2)$, you can follow these steps:

1. First, expand both sides of the inequality:

$(x+3)(x-10) < (x-5)(x+2)$

Expand the left side:

$x^2 - 10x + 3x - 30 < (x-5)(x+2)$

Simplify the left side:

$x^2 - 7x - 30 < (x-5)(x+2)$

2. Now, expand the right side:

$x^2 - 5x + 2x - 10 < x^2 - 5x + 2x - 10$

Both sides are equal, so we have:

$x^2 - 7x - 30 < x^2 - 7x - 30$

3. Notice that the $x^2$ terms cancel out on both sides, leaving you with:

$-30 < -30$

4. Since $-30$ is not less than $-30$ (it's equal to $-30$), there are no values of $x$ that satisfy the inequality. In other words, there are no solutions to the inequality.

So, the solution to the inequality $(x+3)(x-10) < (x-5)(x+2)$ is the empty set, meaning there are no values of $x$ that make the inequality true.