Question

3×(x-5) + 10×(x-8)= 30​

Answer 1

3•(x-5)+10•(x-8)=30

3x-15+10x-80=30

переводим в подобные члены

13x-95=30

переносим константу в правую часть и меняем знак

13x=30+95

13x=125

x=125:13

x=9,61

Answer 2

To solve the equation 3x(x - 5) + 10(x - 8) = 30, you'll need to follow these steps:

1. Distribute the constants (3 and 10) into the parentheses on both sides of the equation:

3x(x) - 3x(5) + 10x - 80 = 30

This simplifies to:

3x^2 - 15x + 10x - 80 = 30

2. Combine like terms:

3x^2 - 5x - 80 = 30

3. Move the constant term to the right side of the equation by adding 80 to both sides:

3x^2 - 5x - 80 + 80 = 30 + 80

This simplifies to:

3x^2 - 5x = 110

4. Now, we have a quadratic equation. To solve for x, you can set the equation equal to zero:

3x^2 - 5x - 110 = 0

5. To solve the quadratic equation, you can use the quadratic formula:

x = (-b ± √(b² - 4ac)) / (2a)

In this case, a = 3, b = -5, and c = -110. Plug these values into the quadratic formula:

x = (-(-5) ± √((-5)² - 4(3)(-110))) / (2(3))

x = (5 ± √(25 + 1320)) / 6

x = (5 ± √1345) / 6

So, the solutions for x are:

x₁ = (5 + √1345) / 6 x₂ = (5 - √1345) / 6

These are the two possible values of x that satisfy the original equation.