Question

(Х+4)²= (а+5)(а+5)= Х²-100= (а-в)(а+в)=

Answer 1

Відповідь:

(Х+4)² = (X+4)(X+4) = X² + 8X + 16

(а+5)(а+5) = а² + 10а + 25

Х²-100 = (Х+10)(Х-10)

(а-в)(а+в) = а² - в²

Пояснення:

(Х+4)² = (X+4)(X+4) = X² + 8X + 16

(а+5)(а+5) = а² + 10а + 25

Х²-100 = (Х+10)(Х-10)

(а-в)(а+в) = а² - в²

Answer 2

It looks like there might be a misunderstanding or error in your expressions. Let's break down each part:

1. $(Х+4)^2$ can be expanded as $Х^2 + 8Х + 16$.
2. $(а+5)(а+5)$ is correctly written as $а^2 + 10а + 25$.
3. $Х^2 - 100$ is a difference of squares and can be factored as $(Х - 10)(Х + 10)$.
4. $(а-в)(а+в)$ is also a difference of squares and can be factored as $а^2 - в^2$.

Now, let's compare these results:

$Х^2 + 8Х + 16 \neq а^2 + 10а + 25$

So, it seems there might be a mistake or inconsistency in your expressions. Please double-check the expressions and ensure they are written correctly. If you have specific values for Х, а, and в, you can substitute them into the expressions to verify their equality.