Question

Arccos( cos 4 пи\4)= tg( arctg ( - 3\5 ))= ctg ( arctg ( - 2\5))=..

Answer 1

В первом задание не понятно записано.

Answer 2

Let's calculate each of these trigonometric expressions step by step:

1. Arccos(cos(4π/4)): The angle 4π/4 is equivalent to π, which is 180 degrees. The cosine of 180 degrees is -1. Therefore, Arccos(-1) = π.

2. tg(arctg(-3/5)): The arctangent (arctg) of -3/5 represents an angle whose tangent is -3/5. To find this angle, you can use the inverse tangent function:

   arctg(-3/5) ≈ -0.5404 radians (approximately)

   Now, you want to find the tangent (tg) of this angle:

   tg(-0.5404) ≈ -0.5463 (approximately)

3. ctg(arctg(-2/5)): The arctangent (arctg) of -2/5 represents an angle whose tangent is -2/5. To find this angle, you can use the inverse tangent function:

   arctg(-2/5) ≈ -0.3805 radians (approximately)

   Now, you want to find the cotangent (ctg) of this angle:

   ctg(-0.3805) ≈ -2.6251 (approximately)

So, the values are:

1. Arccos(cos(4π/4)) = π
2. tg(arctg(-3/5)) ≈ -0.5463
3. ctg(arctg(-2/5)) ≈ -2.6251