Question

2c ( 1 + c ) - ( c -2) (c + 4 )

Answer 1

Если не ошибаюсь, то тут не уравнение, а просто упростить выражение . так как в уравнения чаще всего переменная х 

Answer 2

2с+2с^2-(с^2+4с-2с-8)=2с+2с^2-с^2-4с+2с+8=с^2+8

Answer 3

To simplify the expression 2c(1 + c) - (c - 2)(c + 4), you can use the distributive property and then combine like terms:

1. Distribute the 2c into the terms inside the first parentheses: 2c * 1 + 2c * c

This gives you: 2c + 2c^2

2. Now, distribute the -(c - 2) into the terms inside the second parentheses: -(c - 2) * (c + 4)

Using the distributive property again, we get: -c(c + 4) + 2(c - 2)

3. Distribute the -c into the terms inside the first parentheses: -c * c - c * 4

This gives you: -c^2 - 4c

4. Distribute the 2 into the terms inside the second parentheses: 2 * c - 2 * 2

This gives you: 2c - 4

5. Now, we can put it all together:

   (2c + 2c^2) - (-c^2 - 4c)

6. Remove the parentheses and simplify further:

   2c + 2c^2 + c^2 + 4c

7. Combine like terms:

   2c + 4c + 2c^2 + c^2

8. Combine the terms with 'c':

   (2c + 4c) + (2c^2 + c^2)

   6c + 3c^2

So, the simplified expression is:

3c^2 + 6c