Question

При какомзначении ky=kx + 5 проходитточкуD(6;-19)?

Answer 1

K(-19) = k(6) + 5
-19k = 6k +5
-19k - 6k = 5
-25k = 5
k = 5 / (-25)
k = - 1/5

Answer 2

To find the value of k when the point D(6, -19) lies on the line represented by the equation ky = kx + 5, we need to substitute the coordinates of point D into the equation and solve for k.

Given the coordinates of point D: D(6, -19)

Substitute x = 6 and y = -19 into the equation ky = kx + 5:

-19k = k * 6 + 5

Now, let's solve for k:

-19k = 6k + 5

To isolate k on one side of the equation, we need to move 6k to the left side:

-19k - 6k = 5

Combine like terms:

-25k = 5

Finally, divide both sides by -25 to solve for k:

k = 5 / -25

k = -1/5

So, the value of k for the line passing through point D(6, -19) is k = -1/5.