Question

-5y(-3y-4)(3y-4) решение 7кл

Answer 1

$-5y(-3y-4)(3y-4)=-5y*(-1)*(3y+4)*(3y-4)=\\\\ =5y*[(3y)^2-4^2]=5y*(9y^2-16)=5y*9y^2-5y*16=\\\\ =45y^3-80y$

Answer 2

-80y+45y( в третьей степени)

Answer 3

To simplify the expression, let's perform the multiplication step by step:

-5y(-3y-4)(3y-4)

Step 1: Multiply the first two terms inside the parentheses: -5y * (-3y) = 15y^2

Step 2: Multiply the first term with the second term inside the parentheses: -5y * (-4) = 20y

Step 3: Multiply the first term with the third term inside the parentheses: -5y * (3y) = -15y^2

Step 4: Multiply the second two terms inside the parentheses: (-3y-4) * (3y-4)

Step 5: Multiply the first term with the second term inside the second set of parentheses: (-3y) * (3y) = -9y^2

Step 6: Multiply the first term with the third term inside the second set of parentheses: (-3y) * (-4) = 12y

Step 7: Multiply the second term with the second term inside the second set of parentheses: (-4) * (3y) = -12y

Step 8: Multiply the second term with the third term inside the second set of parentheses: (-4) * (-4) = 16

Now, let's combine all the terms:

15y^2 + 20y - 15y^2 + (-9y^2) + 12y + (-12y) + 16

The like terms (-15y^2 and +15y^2) will cancel each other out, as will the like terms (20y, 12y, and -12y):

= 0 + (-9y^2) + 0 + 16

= -9y^2 + 16

So the simplified expression is:

-9y^2 + 16