Question

Дана функция y=f(x), где f(x) =x^2-5 Найдите f(-3x+2)

Answer 1

$\boxed{f(x)=x^2-5} \\ f(-3x+2)=? \\ \\ f(-3x+2)=(-3x+2)^2-5 \\ f(-3x+2) = 9 x^2 - 12 x + 4 -5 \\ f(-3x+2)=9x^2-12x-1$

Answer 2

F(-3x+2)= (2-3x)²-5=4-12x+9x²-5=9x²-12x-1

Answer 3

To find the value of f(-3x+2), we need to substitute the expression (-3x+2) for x in the function f(x) = x^2 - 5.

So, we have: f(-3x+2) = (-3x+2)^2 - 5

Now, let's simplify the expression:

f(-3x+2) = (-3x+2)(-3x+2) - 5 = (9x^2 - 6x - 6x + 4) - 5 = 9x^2 - 12x - 1

Therefore, the value of f(-3x+2) is 9x^2 - 12x - 1.