Question

(a-3)^2+6a при а=7 Помогите)

Answer 1

(а- 3)² + 6а =  а² - 2*а*3 + 3² +6а = а² - 6а  + 9  + 6а  = а² + 9
при  а =  7  ⇒  7²  +  9 = 49 + 9 = 58

Answer 2

( а - 3 )^2 + 6а при а = 7.
( а^2 - 6а + 9) + 6а = а^2 - 6а + 9 + 6а = а^2 + 9 = 7^2 + 9 = 49 + 9 = 58.
Удачи)))

Answer 3

Sure, I'd be happy to help you with that!

To evaluate the expression (a-3)^2 + 6a when a = 7, follow these steps:

Step 1: Substitute the value of a into the expression: (a-3)^2 + 6a

When a = 7, we get: (7-3)^2 + 6(7)

Step 2: Simplify the expression inside the parentheses first: (7-3)^2 = 4^2 = 16

Step 3: Now, substitute the simplified expression back into the original expression: (7-3)^2 + 6(7) = 16 + 6(7)

Step 4: Perform the multiplication operation: 16 + 6(7) = 16 + 42

Step 5: Finally, perform the addition operation: 16 + 42 = 58

So, when a = 7, the expression (a-3)^2 + 6a evaluates to 58.