Question

(a+7)(a-1)+(a-3)во 2 степени

Answer 1

$(a + 7)(a + 1) + {(a + 3)}^{2} = {a}^{2} + a + 7a + 7 + {a}^{2} + 6a + 9 = 2 {a}^{2} + 14a + 16$

Answer 2

Let's simplify the given expression step by step:

1. Distribute the first term: (a+7)(a-1) (a+7)(a-1) = a(a-1) + 7(a-1)

2. Expand the second term: (a-3)² (a-3)² = (a-3)(a-3) = a² - 3a - 3a + 9 = a² - 6a + 9

Now, let's put everything together:

(a+7)(a-1) + (a-3)²

Substitute the expanded forms of each term:

(a(a-1) + 7(a-1)) + (a² - 6a + 9)

Now, let's simplify further:

(a² - a + 7a - 7) + (a² - 6a + 9)

Combine like terms:

a² + 6a - 7 + a² - 6a + 9

Now, the terms with 'a' cancel each other out:

2a² + 2

So, the simplified expression is:

2a² + 2