Question

(x+5)(x+4)(x-1)x=-6срочно!!!

Answer 1

1)(x+5)((x-1)=x²+5x-x-5=x²+4x-5
2)x(x+4)=x²+4x
3)x²+4x=t
4)(t-5)*t=-6
t²-5t+6=0
D=25-24=1
t=(5±1)/2
t1=3;t2=2
a)x²+4x-3=0
D=16+12=28
x=(-4±√28)/4
b)x²+4x-2=0
D=16+8=24
x=(-4±√24)/4

Answer 2

To solve the equation (x+5)(x+4)(x-1)x = -6, we need to find the value(s) of x that satisfy the equation. Let's solve it step-by-step:

Step 1: Expand the left-hand side of the equation: (x+5)(x+4)(x-1)x = (x^2 + 9x + 20)(x-1)x = x^2(x-1) + 9x(x-1) + 20(x-1)x = x^3 - x^2 + 9x^2 - 9x + 20x^2 - 20x = x^3 + 28x^2 - 29x

So, the equation now becomes: x^3 + 28x^2 - 29x = -6

Step 2: Bring all terms to one side to get a cubic equation: x^3 + 28x^2 - 29x + 6 = 0

Step 3: Now, we need to find the values of x that satisfy this cubic equation. Unfortunately, there is no general algebraic formula for solving cubic equations in the form ax^3 + bx^2 + cx + d = 0. However, we can use numerical methods or calculators to approximate the solutions.

One common numerical method to find the solutions of a cubic equation is the Newton-Raphson method, but it's not something that can be done quickly in a text-based conversation.

If you need the exact solutions or more accurate approximations, it's best to use a calculator or a computer algebra system to solve this cubic equation for you. Otherwise, you can try using an online cubic equation solver to find approximate solutions for the given equation.